Lubwama's double-double lands him Player of the Week award- April 20, 2025Ian Lubwama put on an amazing game in the last round for second-ranked
He got a double-double of 13 points and 10 assists, while his team outclassed, the league's bottom-ranked team Second best performed player last round was Peter Sifuma (C-1996). He is a center in his first season at Jaguars. In the last game Sifuma recorded an impressive double-double of 22 points and 14 rebounds. Of course together with Lubwama he helped JT Jaguars BC with another comfortable win Third place about best performers goes to forward Joseph Chuma (F-1991) of Other top performing players last week: 4. Micheal Otieno (193-G-1993) of Rezlife S. - 24 points and 6 rebounds 5. Arthur Wanyoto) of Blazers - 9 points, 14 rebounds and 5 assists 6. Jimmy Enabu (187-PG-1988) of Blazers - 12 points, 5 rebounds and 8 assists 7. Tong Obde) of Jaguars - 6 points and 20 rebounds 8. Joel Lukoji (2001) of Blazers - 10 points, 5 rebounds and 8 assists 9. Fayed Baale (173-PG-2001) of City Oilers - 17 points, 6 rebounds and 5 assists 10. Malual Dier) of City Oilers - 9 points and 9 rebounds The Player of the week is selected based on efficiency calculation, but also including game result, importance of the game, if played recorded double-double/triple-double, etc. The efficiency formula is a combination of various formulas used by different basketball organizations/leagues. We got involved many basketball scouts and journalists to assure it's accuracy. The formula: 1.5*PTS + 3*(REB+AST+ST+BL-TO) - 2*BSAG - 4*PF + 3*PFRV + 4*(2FGPM+3FGPM) + 1.5*FTM - 3*(2FGPA-2FGPM) - 3*(3FGPA-3FGPM) - (FTA-FTM)
Tags : IAN LUBWAMA, JT JAGUARS BC, UGANDAN BASKETBALL, |
Subscribe
Login












